Question

the sum of numerator and denominator of a fraction is 3 less than twice the denominator if the numerator and denominator are decreased by 1 the numerator becomes how the denominator the fraction​

Answer 1

Answer:

here is your ans.

Answer 2

Answer:

The required fraction is 4/7.

Step-by-step explanation:

let the numerator be x and the denominator be y.

so, the fraction becomes x/y.

CASE 1 :-

x+y=2y-3.

x=2y-3-y.

x=y-3                       _(i)

CASE 2 :-

x-1/y-1 = 1/2.

by cross multiplication.

2(x-1)=1(y-1).

2x-2=y-1.

2x-y= -1+2.

2x-y=1.

substituting the value of x from eq.(i)

2(y-3)-y=1.

2y-6-y=1.

y=1+6.

y=7.

substituting the value of y in eq.(i)

x=7-3.

x=4.

hence, the required fraction is 4/7.

hope it helps you.......