the sum of numerator and denominator of a fraction is 4 more than twice the numerator if 3 is added to each of the numerator and the denominator the ratio becomes 2 ratio 3 find the fraction
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Hey
Here is your answer,
Let the fraction be x/y where x=numerator and y=denominator.
Clearly there are two cases:
Case 1
According to question,
x+y=2x+4
=> -x+y=4
=> x-y=-4---1)
Case 2
According to question,
x+3/y+3=2/3
=>3(x+3)=2(y+3)
=>3x+9=2y+6
=>3x-2y=-3---2)
By elimination method,
we get:
3x-3y=-12----3)
3x-2y=-3------4)
By subtracting 3) and 4),
we get:
-3y+2y=-12+3
=> -y=-9
So, y=9
On substituting y=9 in 4),
we get:
3x-18=-3
3x=15
So, x=5
Here, x=5 and y=9.
Therefore,the fraction is:
x/y = 5/9
Answer: 5/9
Hope it helps you!
Here is your answer,
Let the fraction be x/y where x=numerator and y=denominator.
Clearly there are two cases:
Case 1
According to question,
x+y=2x+4
=> -x+y=4
=> x-y=-4---1)
Case 2
According to question,
x+3/y+3=2/3
=>3(x+3)=2(y+3)
=>3x+9=2y+6
=>3x-2y=-3---2)
By elimination method,
we get:
3x-3y=-12----3)
3x-2y=-3------4)
By subtracting 3) and 4),
we get:
-3y+2y=-12+3
=> -y=-9
So, y=9
On substituting y=9 in 4),
we get:
3x-18=-3
3x=15
So, x=5
Here, x=5 and y=9.
Therefore,the fraction is:
x/y = 5/9
Answer: 5/9
Hope it helps you!
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