the sum of numinetor and demominator of a fraction is 8 . if 3 is added in both numinetor and demominator the fraction become 3/4. find the fraction
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Given :
- The sum of numerator and denominator of a fraction is 8 .
- If 3 is added in both numerator and denominator the fraction become 3/4.
To find :
- The fraction.
Solution :
Let the numerator of the fraction be x and the denominator of the fraction be y.
According to 1st condition :-
- The sum of numerator and denominator of a fraction is 8.
According to 2nd condition :-
- If 3 is added in both numerator and denominator the fraction become 3/4.
Put x=8-y from eq(1).
Now put y = 5 in eq(1) for getting the value of x.
We know,
Therefore, the required fraction,
Answered by
0
f = 3/5
- The sum of numinetor and demominator of a fraction is 8 .
- if 3 is added in both numinetor and demominator the fraction become 3/4.
- The fraction.
Let numerator of the fraction be x and the denominator of the fraction be y.
The sum of numinetor and demominator of a fraction is 8 .
x + y = 8
x = 8 - y_____(1)
if 3 is added in both numinetor and demominator the fraction become 3/4.
x + 3 / y + 3 = 3/4
4x + 12 = 3y + 9
4(8 - y) + 12 = 3y + 9
32 - 4y + 12 = 3y + 9
-4y - 3y = 9 - 32 - 12
-7y = -35
y = 5
x = 8 - y
x = 8 - 5
x = 3
f = x/y
f = 3/5
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