Math, asked by naveenbhaker0, 10 months ago

the sum of numinetor and demominator of a fraction is 8 . if 3 is added in both numinetor and demominator the fraction become 3/4. find the fraction​

Answers

Answered by Anonymous
20

Given :

  • The sum of numerator and denominator of a fraction is 8 .
  • If 3 is added in both numerator and denominator the fraction become 3/4.

To find :

  • The fraction.

Solution :

Let the numerator of the fraction be x and the denominator of the fraction be y.

According to 1st condition :-

  • The sum of numerator and denominator of a fraction is 8.

\implies\sf{x+y=8}

\implies\sf{x=8-y.........eq(1)}

According to 2nd condition :-

  • If 3 is added in both numerator and denominator the fraction become 3/4.

\implies\sf{\frac{x+3}{y+3}=\frac{3}{4}}

\implies\sf{4x+12=3y+9}

Put x=8-y from eq(1).

\implies\sf{4(8-y)+12=3y+9}

\implies\sf{32-4y+12=3y+9}

\implies\sf{-4y-3y=9-32-12}

\implies\sf{-7y=-35}

\implies\sf{7y=35}

\implies\sf{y=5}

{\boxed{\bold{y=5}}}

Now put y = 5 in eq(1) for getting the value of x.

\implies\sf{x=8-y}

\implies\sf{x=8-5}

\implies\sf{x=3}

{\boxed{\bold{x=3}}}

We know,

{\boxed{\bold{Fraction=\dfrac{Numerator}{Denominator}}}}

Therefore, the required fraction,

\sf{Fraction=\dfrac{x}{y}=\dfrac{3}{5}}

Answered by silentlover45
0

  \huge \mathfrak{Answer:-}

f = 3/5

\large\underline\mathrm{Given:-}

  • The sum of numinetor and demominator of a fraction is 8 .
  • if 3 is added in both numinetor and demominator the fraction become 3/4.

\large\underline\mathrm{To \: find}

  • The fraction.

\large\underline\mathrm{Given:-}

Let numerator of the fraction be x and the denominator of the fraction be y.

The sum of numinetor and demominator of a fraction is 8 .

\implies x + y = 8

\implies x = 8 - y_____(1)

if 3 is added in both numinetor and demominator the fraction become 3/4.

\implies x + 3 / y + 3 = 3/4

\implies 4x + 12 = 3y + 9

\large\underline\mathrm{put \: x \: = \: 8 \: - \: y \: from \: Eq. \: (1)}

\implies 4(8 - y) + 12 = 3y + 9

\implies 32 - 4y + 12 = 3y + 9

\implies -4y - 3y = 9 - 32 - 12

\implies -7y = -35

\implies y = 5

\large\underline\mathrm{Now, }

\large\underline\mathrm{put \: y \: = \: 5 \: in \: Eq. \: (1).}

\implies x = 8 - y

\implies x = 8 - 5

\implies x = 3

\large\underline\mathrm{fraction \: = \: Numerator \: / \: denominator}

f = x/y

f = 3/5

\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}

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