Question

The sum of opposite angles of a parallelogram is 150°. Find all the angles of a parallelogram .
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Answer 1

Answer:

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Explanation:

We know that opposite angles of parallelogram are equal.

All the angles of parallelogram add upto 360°

Let the four angles of parallelogram be \angle{}∠ A, \angle{}∠ B, \angle{}∠ C and \angle{}∠ D

Let \angle{}∠ D be x

So, its opposite is \angle{}∠ B

So, \angle{}∠ B = x

Let \angle{}∠ A be 150°

\angle{}∠ C is opposite angle of \angle{}∠ A

So, \angle{}∠ A = 150°

According to the question,

\angle{}∠ A + \angle{}∠ B + \angle{}∠ C + \angle{}∠ D = 360

150° + x + x = 360

2x = 360 - 150

2x = 210

x = \dfrac{210}{2}

2

210

x = 105

\therefore{}∴ \angle{}∠ B => x => 105°

So, \angle{}∠ D => x => 105°

\therefore{}∴ m\angle{}∠ A = 150°

\angle{}∠ C = 150°

\angle{}∠ B = 105°

\angle{}∠ D = 105°

Answer 2

Answer:

If all angles are a,b,c, and d

Explanation:

If sum of all angles are = 360 degree,

Angle a + b = 150 degree

Then,

Angle b + c = 210 degree,

Then,

We can say that ,

Angle b = 105 degree and

angle c = 105 degree.

I think u got it.

Thank u.