Math, asked by avaneesh6349, 1 year ago

The sum of present ages of a and b is 68 years 2 years hence a's age will be 3 times that of b's age what are their present age

Answers

Answered by aathi39
1

Step-by-step explanation:

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Answered by ColinJacobus
3

Answer:  The present age of A is 52 years and that of B is 16 years.

Step-by-step explanation:  Given that the sum of the present ages of A and B is 68 years. 2 years hence, A's age will be 3 times that of B's age.

We are to find the present ages of A and B.

Let x and y represents the presents ages of A and B in years

Then, according to the given information, we have

x+y=68\\\\\Rightarrow x=68-y~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

x+2=3(y+2)\\\\\Rightarrow x+2=3y+6\\\\\Rightarrow 68-y+2=3y+6\\\\\Rightarrow 3y+y=70-6\\\\\Rightarrow 4y=64\\\\\Rightarrow y=\dfrac{64}{4}\\\\\Rightarrow y=16.

From equation (i), we get

x=68-16=52.

Thus, the present age of A is 52 years and that of B is 16 years.

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