Math, asked by Ishu77911, 1 year ago

There are 2 different blue toys, 3 different green toys and 4 different red toys. In how many ways one can choose 3 toys, such that there is at least one green toy in the chosen three? (a) 33 ways (b) 36 ways (c) 38 ways (d) 40 ways

Answers

Answered by aditigupta41
0

Answer:

36 is the answers fo this question

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