the sum of present ages of sibu and hari is 50.years.ten years ago hari was 5 times asold as sibu.how old are they now?
Answers
Answered by
8
x + y = 50. (1)
(x - 10) - 5 (y - 10). (2)
x - 10 - 5y + 50
x - 5y + 40. (3)
elimination of (1) and (3)
x + y = 50
x - 5y = - 40
-. +. +
6y = 90
y = 15
now... substitute y in (1)
x + y = 50
x + 15 = 50
x = 35
(x , y) = ( 35 , 15)
(x - 10) - 5 (y - 10). (2)
x - 10 - 5y + 50
x - 5y + 40. (3)
elimination of (1) and (3)
x + y = 50
x - 5y = - 40
-. +. +
6y = 90
y = 15
now... substitute y in (1)
x + y = 50
x + 15 = 50
x = 35
(x , y) = ( 35 , 15)
Answered by
13
let sibu present age be x years then hari present age is (50-x)years
ten years ago,
sibu age was (x-10)years
and hari age was (50-x-10)=(40-x)years
A/Q
40-x=5(x-10)
=>40-x=5x- 50
=>40+50=5x+x
=>90=6x
=>x=90/6=15
present age of sibu is 15years and that of hari is (50-15)=35years
if the answer helped u mark it as brilliant
ten years ago,
sibu age was (x-10)years
and hari age was (50-x-10)=(40-x)years
A/Q
40-x=5(x-10)
=>40-x=5x- 50
=>40+50=5x+x
=>90=6x
=>x=90/6=15
present age of sibu is 15years and that of hari is (50-15)=35years
if the answer helped u mark it as brilliant
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