Math, asked by rohan3136, 1 year ago

the sum of present ages of sibu and hari is 50.years.ten years ago hari was 5 times asold as sibu.how old are they now?

Answers

Answered by hiraljain
8
x + y = 50. (1)

(x - 10) - 5 (y - 10). (2)
x - 10 - 5y + 50
x - 5y + 40. (3)

elimination of (1) and (3)

x + y = 50
x - 5y = - 40
-. +. +
6y = 90
y = 15

now... substitute y in (1)

x + y = 50
x + 15 = 50
x = 35

(x , y) = ( 35 , 15)

Answered by vivek007146
13
let sibu present age be x years then hari present age is (50-x)years
ten years ago,
sibu age was (x-10)years
and hari age was (50-x-10)=(40-x)years
A/Q
40-x=5(x-10)
=>40-x=5x- 50
=>40+50=5x+x
=>90=6x
=>x=90/6=15
present age of sibu is 15years and that of hari is (50-15)=35years
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