Question

the sum of product of the zeros of a polynomial 4 and 1 respectively then the polynomial is

Answer 1

Step-by-step explanation:

if it is a quadratic equation then ,

x^2-(a+b)+ab=0,

since a+b=4 and ab=1,

we get x^2-4x+1=0

Answer 2

hey mate. here's your answer

Step-by-step explanation:

Given,

sum of zeroes, (alpha + beeta) = 4

product of zeroes(alpha × beeta) = 1

So,

req. polynomial,p(x)= x square - (sum of zeroes)x + (product of zeroes)

= x square -(4)x + (1)

= x square -4x +1.

hope it helps...