The sum of recipocals of two consecutive odd number is 12 upon 35 find those answers
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let the numbers be x and (x+2)
according to the question
1/x + 1/(x+1)= 12/35
=>[(x+1)+x]/(x)(x+ 1 ) = 12/35
=>2x + 1 / x² + X = 12/35
=>70x + 35 = 12x² + 12x
=>58x - 12x² + 35 = 0
=>12x²- 58x - 35 = 0
=>plz solve it urself
according to the question
1/x + 1/(x+1)= 12/35
=>[(x+1)+x]/(x)(x+ 1 ) = 12/35
=>2x + 1 / x² + X = 12/35
=>70x + 35 = 12x² + 12x
=>58x - 12x² + 35 = 0
=>12x²- 58x - 35 = 0
=>plz solve it urself
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