the sum of roots of the quadratic equation3x2-9x+5=0 is
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3x²-9x+5 = 0.
multiplying the equation by 3.
9x²-27x+15 =0.
(3x)² - 2 * 3x * 9/2 + (9/2)² - (9/2)² + 15 = 0.
(3x - 9/2)² - 81/4 + 15 = 0.
(3x - 9/2)² -21/4 = 0.
(3x - 9/2 )² = 21/4.
3x - 9/2 = +/- √21/4.
3x = +/- √21/4 + 9/2.
X = (+/-√21/4 + 9/2) ÷ 3.
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so, the 1st root is,
X= (√21/4 + 9/2) ÷ 3.
and 2nd root is,
X = (-√21/4 + 9/2) ÷ 3.
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