Question

the sum of series 1 square + (1 square + 2 [complete + 1 square + 2 square + 3] + ​

Answer 1

Answer:

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Step-by-step explanation:

Step-by-stWe know that the sum of

{1}^{2} + {2}^{2} + {3}^{2} + ..... + {n}^{2} = \frac{n(n + 1)(2n + 1)}{6}

And

2 \times {2}^{2} + 2 \times {4}^{2} + ....2 \times {(n)}^{2} \\ = 2( {1}^{2} + {2}^{2} + .... + {n}^{2} ) \\ = \frac{n(n + 1)(2n + 1)}{3}

So u can find the value of

{1}^{2} + {3}^{2} + ..... {(2n - 1)}^{2}

Finally, you will be able to solve your question!!

Thank me later!!