The sum of six consecutive integers is -9. find the integres
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let the first consecutive no. be x so other no.s are x+1 ,x+2 ,x+3 ,x+4 ,x+5
so x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)= -9
=(x+x+x+x+x+x) +(1+2+3+4+5)= -9
=6x +15= -9
=6x= -9+15
=6x=6
=x= 6/6
=x=1
Hence ,x=1.
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