Question

The sum of six consecutive odd
Integers is 204

Answer 1

Answer:

Required six consecutive odd integers are 29, 31 , 33 , 35 , 37 , 39 .

Step-by-step explanation:

Let the required six consecutive numbers are 2a + 1 , 2a + 3 , 2a + 5 , 2a + 7 , 2a + 9 , 2a + 11.

According to the question  : -

⇒ Sum of six consecutive odd integers = 204

= >  ( 2a + 1 ) + ( 2a + 3 ) + ( 2a + 5 ) + ( 2a + 7 ) + ( 2a + 9 ) + ( 2a + 11 ) = 204

= >  2a + 1 + 2a + 3 + 2a + 5 + 2a + 7 + 2a + 9 + 2a + 11 = 204

= >  2a + 2a + 2a + 2a + 2a + 2a + 1 + 3 + 5 + 7 + 9 + 11 = 204

= >  12a + 36 = 204

= >  12a = 204 - 36

= >  12 a = 168

= >  a = 168 / 12

= >  a = 14

Therefore, required six consecutive odd integers are : -

2a + 1 = 2( 14 ) + 1 = 28 + 1 = 29

2a + 3 = 29 + 2 = 31

2a + 5 = 31 + 2 = 33

2a + 7 = 33 + 2 = 35

2a + 9 = 35 + 2 = 37

2a + 11 = 37 + 2 = 39