the sum of square of 3 in consecutive integers is 110
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hey mate , here is ur answer
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Step-by-step explanation:
Given the sum of square of 3 in consecutive integers is 110
Let the first integer be 'x'
Second integer be 'x + 1'
Third integer be 'x + 2'
Sum = 110 (given)
⇒ x² + (x + 1)² + (x + 2)² = 110
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