Question

the sum of square of two consecutive positive odd integer is 202 . so find the number

Answer 1

Answer:

Step-by-step explanation:

Let,

1st odd positive number is x + 1

2nd odd positive number is x + 3

then

(x + 1)^2 + (x + 3)^2 = 202

(x^2 + 1 +2x) + (x^2 + 9 + 6x) = 202

2x^2 + 8x + 10 = 202

2x^2 + 8x = 192

x^2 + 4x = 96

x^2 + 4x - 96 = 0

x^2 + 12x - 8x - 96 = 0

x(x + 12) - 8(x + 12) = 0

(x - 8) (x + 12) = 0

Now

we get two value of x but we only consider positive value,

x = 8

x = - 12

Here we have the value of x is 8.

Hence, the 1st odd positive number is 9 and the 2nd odd positive number is 11.