Question

the sum of square of two number is 80. and the square of their difference is 36 find the product of two numbers

Answer 1

Let the numbers be a and b.

=> a^2 + b^2 = 80

=> (a-b)^2=a^2+b^2-2ab

=> (a-b)^2= 36

=> a^2+b^2-2ab = 36

=> 80-2ab = 36

=>80-36 = 2ab

=>44=2ab

=>ab= 22

Ans.= The product of the two numbers is 22.

Hope it hepls!!

Answer 2

let the two no. be X and Y .
now,
x2 + y2 = 80 -------1
(x - y)^2= 36
x2. + y2 -2xy = 36
by equation 1
80 -2xy = 36
-2xy = 36-80
-2xy = -44
xy = 22.
thus ,
the product of their no. is 22.
I hope it help u.....
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