Question

The sum of squares of three positive integers is 323. If the sum of squares of two numbers is twice the third, their product is

Answer 1

let x , y and z are three positive numbers
a/c question
x^2+y^2+z^2=323-----(1)
also,
x^2+y^2=2z
put this value in equation (1)
z^2+2z-323=0
z={-2+_root (4+1292)}/2
=17
hence z=17
now
x^2+y^2=34
if we think x=5 and y=3
integer value then
25+9=34
hence
x=5 , y=3 and z=17
now product of three numbers are =17 x 5 x 3=255

Answer 2

Here u go , for the answer!