Question

the sum of squares of to consecutive positive integers is 145 . find the integers of the word problem stated above .​

Answer 1

Step-by-step explanation:

let the first consecutive integer=x

second consecutive integer=x+1

square of both Integers

x²+(x+1)²=145

x²+x²+1+2x=145 [by applying formula (a+b)²]

2x²+2x-144=0

by splitting middle term

2x²+ 18 x - 16 x-144 =0

2x(x+9)-16(x+9)=0

(2x-16)(x+9)=0

2x-16=0 or x+9=0

2x= 16. | x= -9

x= 16/2. |. (not possible) value)

x=8. |

hence,

first integer x =8

second integer X + 1 = 9

please mark my answer as brainiest.