the sum of squares of two consecutive natural number is 244;find the numbers
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Let two consecutive natural number will be x and x+1
x^2 + (x+1)^2 = 244
x^2 x^2 +1 + 2x = 244
2x^2 + 1 + 2x = 244
2x^2 + 2x -243=0
solve this equation and get the number
x^2 + (x+1)^2 = 244
x^2 x^2 +1 + 2x = 244
2x^2 + 1 + 2x = 244
2x^2 + 2x -243=0
solve this equation and get the number
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