the sum of squares of two consecutive natural numbers is 244.find the number?
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Hii friend!!!!
Let the two consecutive natural number is x,x+1
A.T.S
x^2+(x+1)^2 = 244
x^2+ x^2+1+2x = 244
2x^2 +2x = 244-1
2x^2 +2x = 243
2x^2 +2x-243 =0
THANKS
HOPE IT HELPS U☆☆☆
Let the two consecutive natural number is x,x+1
A.T.S
x^2+(x+1)^2 = 244
x^2+ x^2+1+2x = 244
2x^2 +2x = 244-1
2x^2 +2x = 243
2x^2 +2x-243 =0
THANKS
HOPE IT HELPS U☆☆☆
metro1:
then further it is not solve able because factors are not getting
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