The sum of squares of two consecutive natural numbers is 313 , find the numbers.
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let the numbers be x,x+1
so, x2+(x+1)^2=313
x2+x2+2x+1=313
2x^2+2x=312
(/2) x2+x=156
by quadratic formula,
x= -b+- √b2-4ac/2
= -1 +- √1*1 -4*1*-156 /2
= -1+- √1+624/2
= -1+- √625/2
=-1+-25/2
=-1+25/2, -1-25/2
=24/2 ,-26/2
= 12, -13
given numbers are natural . so x= 12 and x+1=13
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