The sum of successor of 'n' and predecessor of 'n' is
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The sum of successor of 'n' and predecessor of 'n' is. A. n. B. n2. C. 2n. D. None of these. Answer. Successor of n=n+1.
Successor of n=n+1.
Predecessor of n=n−1.
∴ Sum of (n+1)+(n−1),
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Concept: Successor: The successor of a given number is the one that comes right after it.
Predecessor: A number's predecessor is the one that immediately precedes it.
A full number's predecessor is one less than the provided number.
Given: The number 'n'
To find: Sum of successor of 'n' and predecessor of 'n'
Solution: Successor of n = n + 1
Predecessor of n = n - 1
Therefore, sum of successor of 'n' and predecessor of 'n' will be
(n + 1) + (n - 1)
n + 1 + n - 1
2n
Hence, sum of successor of 'n' and predecessor of 'n' will be 2n.
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