Question

the sum of ten terms of AP whose last term is 28 is 148 find first term and common difference

Answer 1

Step-by-step explanation:

S10=148

tn=28......given

now, Sn=n/2(tn-t1)

S10=10/2(28-t1)....let t1 be y

148=5(28-y)

148=140-5y

148-140=5y

8=5y

y=8/5