The sum of the 1
st and 3
rd terms of an A.S is 20, and the sum of 2
nd and 4
th
terms is 26. What is an arithmetic Progression?
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Given ,
The sum of 1st and 3rd term of AP is 20
So ,
and
The sum of 2nd and 4th term of AP is 26
So ,
Subtract eq (i) from eq (ii) , we obtain
2a + 4d - (2a + 2d) = 26 - 20
4d - 2d = 6
2d = 6
d = 3
Put the value of d = 3 in eq (i) , we obtain
2a + 2(3) = 20
2a + 6 = 20
2a = 14
a = 7
Hence , the required AP is -
7 , 10 , 13 , 16 , .....
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