the sum of the 4th and 8th term of an ap is 24 and the sum of 6th and 10th term of ap is 44 then the first three terms of an ap
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hey mate, here is your ans.
the first three terms of A. P are -13, -8, -3
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a+3d+a+7d=24
=2a+10d =24
=a+5d=12. (1)
then a+5d+a+9d=44
=2a+14d=44
=a+7d=22. (2)
solving equation (1) and (2)
using elimination method
a+5d=12
a+7d=22
-. -. =-
0-2d=-10
=2d=10
d=5
then putting this value d=5 in equation (1)
a+5d=12
a+5×5=12
a+25=12
a=-13
then first three terms are a,a+d,a+2d
then -13,-8,-3 is the answer.
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