Question

The sum of the 4th and 8th term of an ap is 32 and the sum of the 6th and 10th term is 47 find the first four terms of the ap

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

so by using the formulas of A.P

a4=a+3d ........1st

similarly

a8=a+7d....2nd

by solving 1 and 2

it is given that the sum of 4th and 8th term is 32 so,

(a+3d)+(a+7d)=32

so,2a +10d=32 ..........3rd

similarly

a6=a+5d......4th

and a10=a+9d.....5th

it is given that sum of 6th an 10th term is 47

so,a6+a10

(a+5d)+(a+9d)=47

2a+14d=47.....6th

so by solving 3rd and 6th

2a+10d=32

2a+14d=32

____________

0-4d=0

-4d=0

d=4

put d in equation 5th

2a+10×4=32

2a+40=32

2a=32-40

a=-8/2

a=4

so by using a and d in we can get the first 4 terms

a1=a

a1=4

a2=a+d

=4+4=8

so a2=8

a3=a+2d

a3=4+2×4

a3=4+8

a3=12

a4=a+3d

a4=4+3×4

a4=4+12

a4=16

so this are the 1st four terms .....

thank you ..,hope this will help you....