Question

The sum of the 4th and 8th terms of an AP is 24 and the sum of the 6th and 10th terms is
44. Find the first three terms of the AP.​

Answer 1

Answer:

-38,-28,-18 are the first three terms of A. P

Step-by-step explanation:

we know that t n=a+(n-1)*d

therefore 4th term=a+3d

8th=a+7d

6th=a+5d

10th=a+9d

from given conditions,

4th term+8th term=24

a+3d+a+7d=24

2a+10d=24.............(1)

6th term +8th term =44

a+5d+a+7d=44

2a+12d=44........(2)

subtract (1)from(2)

2a+12d=44. (solved using linear eq.)

2a+10d=24

2d=20

d=20/2=10. d=10

put value of d in(1)

2a+10d=24

2a+10*10=24

2a+100=24

2a=24-100

2a=-76. a=-76/2. a=-38

we know that first 3 terms can be written as,

a=-38

a+d=-38+10=-28

a+2d=-38+2*10=-38+20=-18

Answer 2

Answer:

-38,-28 & -18 are the first three term of of the ap