Question

The sum of the 4th and 8th terms of an AP is 24 and the sum of the 6th and 10th term is 44. Find the first three terms of the AP.​

Answer 1

heya,,.....


there is your answer .......


pls mark as brainlist.....♥️♥️

Answer 2

$\huge\bold{Solution}$

___________________________________

Given:-

a(4) + a(8) = 24.....(I)

a(6) + a(10) = 44......(II)

Find:-

a(first term) , a + d (second term) , a + 2d(third term)

Firstly we should find d(common difference),

a(4) + a(8) = 24

a(6) + a(10) = 44

we can also write it as,

a + 3d + a + 7d = 24.....(ia) => 2a + 10d = 24

a + 5d + a + 9d = 44 ....(iia) => 2a + 14d = 44

From eqn (ia) and (iia) we get,

d = 5

Now, put the value of d in eqn (ia)

=> 2a + 10 × 5 = 24

=> 2a + 50 = 24

=> 2a = -26

=> a = -13

So, first term (a) of an AP is -13..

we can find other 2 terms by,

a + d = -13 + 5 = -8

a + 2d = -13 + 5 × 2 = -3

So,

the first three terms of an AP are -13 , -8 and -3

Hope it helps u out ♤♤♤