the sum of the 4th and the 6th term of an ap is zero and product of 6th and 9th term is 36 prove that 5 term is zero
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Thus a+4d=0 i. e. fifth term be zero.
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Answer:
Step-by-step explanation:
a+3d+a+5d=0
2a+8d=0 a+4d=0 a= -4d---->1
(a+5d) (a+8d)= 36 (sub 1)
(-4d+5d) (-4d+8d) = 36
(d) (4d) = 36
4d^2=36
d^2=9
d=3
a=-4x3
a=-12
5th term
=> a+4d= -12+4(3)
= -12+12
=0
hence proved
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