The sum of the age of a man and his son is 45 years. Four years ago, the product of their ages was 160 . Find their present ages.
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looking hard question I don't know
ravikumarnarhwal:
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Let sons age be =x
Fathers age = (45-x)
(x-5) (45-x-5) hence x-5 = 4
so x= 9
therefore there ages are 36 and 9
Fathers age = (45-x)
(x-5) (45-x-5) hence x-5 = 4
so x= 9
therefore there ages are 36 and 9
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