Question

The sum of the ages of 10 children born at the intervals of 3 years each is 80 years. what is the age of the youngest child?

Answer 1

Let the age of the 10 children be x,(x+3),(x+6),(x+9),(x+12),(x+15),(x+18),(x+21),(x+24),and (x+27)

According to the question,
x+(x+3)+(x+6)+(x+9)+(x+12)+(x+15)+ (x+18)+(x+21)+(x+24)+ (x+27)=80
=>10x+135=80
=>10x=80-135
=>x= -55/10
=>x= -5.5

As the answer is -ve, the youngest child will born in 5.5 Years.

Answer 2

Answer:

The answer is -5.5 years

Step-by-step explanation:

Let the ages of the 10 children be

x

(x+3)

(x+6)

(x+9)

(x+12)

(x+15)

(x+18)

(x+21)

(x+24)

(x+27)

According to the question,

x+(x+3)+(x+6)+(x+9)+(x+12)+(x+15)+ (x+18)+(x+21)+(x+24)+ (x+27)=80

10x+135=80

10x=80-135

x= -55/10

x= -5.5

The age of the youngest child will be -5.5 years