the sum of the ages of A and B is five fourth the age of C . if the age of A is two third the age of B and sum of all the three is 90 years then find the age (in years) of A.
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Step-by-step explanation:
A+B=5/4c...given...1
A=2/3B.....given...2
A+B=5/4C...From1
2/3B+B=5/4C....from2
2B+3B/3=5/4C
5B/3=5/4C
5B/3×4/5=C
4B/3=C....3
AGE OF A + AGE OF B+ AGE OF C=90....given
A+B+C=90
2/3B+B+4B/3=90....from2&3
2B+3B+4B=270......multiplying by 3
9B=270
B=270/9
B=30
Putting B=30 yrs in 2
A=2/3B
A=2/3×30
A=10 yrs
Hence ageof A is 10 years
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