the sum of the ages of a father and his daughter is 85yrs. five years ago, the father was exactly four times as old as his daughter. the present age of the father is?
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Answer:
Step-by-step explanation:
x+y=85
x-5=4(y-5)
x-5=4y-20
therefore x=4y-15
substituting in 1 we get
5y-15=85
5y=100
therefore y=20
x=85-y
65
thus values of x and y are 65 and 20 respectively
x=69
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