Question

the sum of the ages of a father and his son is 45 years. five years ago, the product of their ages was 150 . find their present ages.

Answer 1

soln:

Let Current Age of Father is x, then current age of son is (45-x)

a/q: (x -5)(45 - x - 5) = 150

=> ( x - 5)( 40 - x ) = 150

=> (x - 5)(x - 40) + 150 = 0

=> x ^2 - 45x + 350 = 0

=> (x - 35)(x - 10) = 0

=> either x = 35 or x = 10

Father's current age : 35
Son's current age : 10

Answer 2

Hii dear here is your answer.....

◆let age of father be y
....................son be x
According to question....

x+y=45------------(1)
five year ago

so ...
(x-5)(y-5)=150-----------(2)

from equation 1 x=45-y

Now put value in equation 2
(45-y-5)(y-5)=150
(40-y)(y-5)=150
40y-200-y^2+5y=150
-y^2+45y-350=0
take - as common
y^2+45y-350
y^2-35y-10y-350
y(y-35)+10(y-35)
y=35

and y=-10 the age will not in - so we will take 35

now put value in equation 1

x+y=45
x=45-y
x=45-35
x=10


so the age of the son is 10years and age of father is 35 years ......


hope it helps you....☺☺☺