Question

The sum of the ages of a father and son is 45 years. 5 years ago, the product of their ages was 34. Their present ages in years are

Answer 1

Answer:

Step by step explanation:

Let the age of son be x and father age is 45 - x years.

Five years ago,

Son's age is x-5 years

Father's age is 45-x-5= 40-x years

A.T.Q

(40-x)(x-5) =34

or

40x- 200- x²+5x= 34

or

-x²+45x-234=0

or

x²-45x+234=0

or

x²-6x-39x+234=0

or

x(x-6)-39(x-6)= 0

x=6 , x=39

If son's age 6 year's then father's age is (45-x)= 45-6= 39 years.

Hence' son's age is 6 years and father's age is 39 years.

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