The sum of the ages of a father and son is 52 years.Five years ago, the age of the father was five times the age of the son. Find their present age?
Answers
Answered by
2
let their present ages be
father=f
son=s
then, f+s= 52.......(i)
5 years ago, father=f-5
son=s-5
given, f-5=5(s-5)
f-5=5s-25
5s-f=25+5
5s-f=20.............(ii)
after solving,
s=12
f=40
father=f
son=s
then, f+s= 52.......(i)
5 years ago, father=f-5
son=s-5
given, f-5=5(s-5)
f-5=5s-25
5s-f=25+5
5s-f=20.............(ii)
after solving,
s=12
f=40
Answered by
16
Answer:
Solution : Let the age of son = x years
And the age of father = 3x years
According to question
X + 3x = 52
4x = 52
X = 52/4
X =13
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