Question

The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man’s age at the time. Find their present ages.

Answer 1

Step-by-step explanation:

let the son's age be and father's age be 4x(before five years)

after five years;

son's age be x+5 and father's age be 4x+5

according to question:

(x+5) + (4x+5) = 45

→ x+5+4x+5 = 45

→ 5x+10 = 45

→ 5x=45-10=35

→ x= 35/5= 7

son's present age is x+5 = 7+5 = 12

father's present age is 4x+5= (4×7)+5= 33

thanks for asking....