Question

the sum of the ages of a man and his son is 45 years. five years ago the product of there ages was four times the man's age at the time. find there present ages

Answer 1

SOLUTION :  

Let the ‘x’ years be the present age of the son  

Given : sum of present ages of man and his son is 45 years.

Man’s present age = (45 – x)years

Five years ago :  

Man’s age = (45 – x - 5) = (40 - x) years

son’s age = (x - 5)years

A.T.Q

Product of their ages was four times the man’s age at the time.

(40 – x) (x – 5) = 4(40 – x)

x – 5 = 4

[(40 – x) got cancelled]

x = 4 + 5  

x = 9 years

Son’s present age = x = 9 years

Man’s present age = (45 – x) years = (45 – 9) years = 36 years

Hence, Son’s present age = 9 years and Man’s present age = 36 years  

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