the sum of the angles of a triangle is equal to the third sides. find the measures of a third angle.
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Let the three sides be
a,b and c.
Given a=b
We know that sum of the angles of a triangle is 180°
This means
a+b+c = 180°
But b=a
Thus,
a+a+c = 180°
2a +c = 180°........Eq[1]
Also given,
2a=c.....Eq[2]
Put Eq[2] in Eq[1]
We get,
2a+2a = 180°
4a=180°
a=45°..
b=45°
c=2a=2×45°
thus c=90°.
Thanks
a,b and c.
Given a=b
We know that sum of the angles of a triangle is 180°
This means
a+b+c = 180°
But b=a
Thus,
a+a+c = 180°
2a +c = 180°........Eq[1]
Also given,
2a=c.....Eq[2]
Put Eq[2] in Eq[1]
We get,
2a+2a = 180°
4a=180°
a=45°..
b=45°
c=2a=2×45°
thus c=90°.
Thanks
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answer 30,60,99
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