Question

The sum of the areas of two squares is 400 sq.m. If the difference
between their perimeters is 16 m, find the sides of two squares.
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Answer 1

Answer:

Let the sides of the two squares be x cm and y cm where x > y. Then, their areas are x2 and y2 and their perimeters are 4x and 4y. Since the value of y cannot be negative, the value of y =12. Thus, the sides of the two squares are 16 cm and 12 cm.