The sum of the average of three consecutive odd numbers and three consecutive even numbers is 21. if the highest even number is 16, what is the lowest odd number
Answers
then
2nd even no. =2x+2
3rd even no. = 2x+4
Given highest even no.=16
so
2x+4=16
2x=12
x=6
so Ist even no.= 2×6 =12
2nd even no.= 14
3rd even no. = 16
average of sum of even no = (12 + 14 + 16)/3
= 42/3
= 14
let 1st odd no. = 2p+1
then
2nd odd no. = 2p+3
3rd odd no. = 2p+5
average sum of odd no. = (2p+1 + 2p+3 + 2p+5)/3
=(6p+9)/3
=2p+3
A.T.Q.
avg sum of even no. + avg sum of odd no. =21
14 + 2p+3=21
2p + 17= 21
2p = 4
p =2
so smallest odd no is 2p +1
i.e.
2×2 +1
=5
The lowest odd number = 5
To find:
the lowest odd number = ?
Given data:
The sum of the average of three consecutive odd numbers and three consecutive even numbers = 21
the highest even number = 16
Formula:
Solution:
let three consecutive odd numbers = p, p+2, p+4
and three consecutive even numbers = p, p+2, p+4
we know the highest even number = 16
then, other lowest even number is p + 4 = 16
p = 16 - 4
= 12
and middle even number p + 2 = 14
12 + 14 + 16 = 42 ÷ 3
= 14
total average - average of even number = average of odd number
21 - 14 = 7
thus the average of odd number = 7
sum of the three consecutive odd numbers = average of odd number x 3
7 X 3 = 21
we know that three consecutive even numbers = p, p+2, p+4, then
p + p + 2 + p + 4 = 21
3P + 6 = 21
3P = 21 - 6
3P = 15
lowest odd number P = 5
middle odd number p + 2 = 7
highest odd number p + 4 = 9
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