Question

The sum of the cubes of first three natural number is equal to
a - (1+2+3) ³
b - (1+2+3) ²
C - 3³
d - 3²
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Answer 1

Answer:

Option B is correct✅️✅️

verification:-

1^3=1

2^3=8

3^3=27

1^3+2^3+3^3=1+8+27=36

now just check if we get 36 as a answer from above options..

1-(1+2+3)^3=6^3=216.....(which is not equal to 36)

2-(1+2+3)^2=6^2=36

Therefore option B is correct