Question

There are two containers containing gases, one at pressure 30 atm and volume 20 mL, and the other at pressure 25 atm. What will be the volume of the container when two are mixed?

(A) 24 mL (B) 20 mL (C) 26 mL (D) 28 mL​

Answer 1

The correct one is 24 mL

Answer 2

By applying Boyle's Law, the answer will 24mL.

Explanation:

According to  Boyle's Law,

$P_2V_2= P_1V_1$ (since the temperature is constant).

From the question,

$V_1 = 20mL\\P_1= 30 atm\\V_2= ?\\P_2 = 25 atm$

By applying the formula,

$P_2V_2 = P_1V_1\\So,\\V_2 = \frac{P_1V_1}{P_2}$

Now putting the value,

$V_2 = \frac{30*20}{25}\\V_2 = 24$

So, the answer is 24mL.