Question

the sum of the digit number is 12 if the digits are interchanged the number is incresed by 18 find the number​

Answer 1

If the first digit is represented as a and the second is represented as b:

Then the number n = 10a + b and it’s reverse is 10b + a.

The rules are:

a + b = 12

And

(10b + a) - (10a + b) = 18

This simplified is:

10b + a - 10a - b = 18

9b - 9a = 18

We can factor out 9

9(b - a) = 18 and simplify

b - a = 2

b = 2 + a we can use this to solve for a using:

a + b = 12

a + (2 + a) = 12 Simplify

2a + 2 = 12

2a = 10

a = 5 Now we solve for b

b - a = 2

b - (5) = 2

b = 7

So a = 5 and b = 7 and we can find the number n by using the ewuation we had before:

n = 10a + b

n = 10(5) + 7

n = 50 + 7

n = 57

The answer is 57

Hope it helps you.. ✌️ ☺