Question

The sum of the digit of 2 digit number is 7. if the digit r reversed, the new number increased by 3 less than 4 times the original number . find the original number.

Answer 1

Hey!!!!

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let the unit digit of the number be x and ten's digit be y.

Then ATQ,

=> (x + y = 7)6
=> 6x + 6y = 42 --------(1)

and

=> 10y + x -+3 = 4(10x + y)

=> 10y + x + 3 = 40x + 4y

=> 39x - 6y = 3 -------(2)

Add (1) and (2)

=> 39x - 6y + 6x + 6y = 3 + 42

=> 45x = 45

=> x = 1

Using x in Original (1)

=> 1 + y = 7

=> y = 6

Original Number = 16

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Hope this helps ✌️