Question

The sum of the digit of a 2-digit number is 10.when 18 is subtracted from the from the number, the digits are reversed. find the numbers.

Answer 1

This is your answer correct

Answer 2

Heya,

Let me answer......

It is given that the sum of the two digits of a two digit number is 10.

Let the ones place digit be x and tens place digit be y.

Therefore, x + y= 10                     -------(i).

It is also given that if 18 is subtracted from the number, the digits will get reversed.
The actual digit will be 10y+x and reversed one will be 10x+y.

So, 10y + x - 18 = 10x + y
=> 10y - y -18 = 10x - x
=> 9y - 18 = 9x
=> 9y - 9x = 18

Taking out common.
y - x = 2                      ----------(ii).

From -----(i) and -----(ii), we get

       y + x = 10
       y -  x =  2
------------------------
       2y    =  12

Hence, y = 6.
Putting this value in equation ----(i), we get 
x = 4.
Hence, the actual digit 10y + x (i.e, 10 X 6 + 4) = 64 and reversed one, 10x + y (i.e, 10 X 4 + 6) = 46.

Hope it  helps.....