the sum of the digit of a 2digit number is 8 the no. obtained by interchanging the digit exceed the given no. by 18 find the given number
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here is the required answer...
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Let the unit digit be y and tens digit be x.
Then, the number = 10x+y
Number by interchanging the digit= 10y+x
According to the question,
x+y=8______________________(i)
10y+x=(10x+y)+18
9x-9y=-18
x-y=-2______________________(ii)
On solving (i) and (ii)...
We get values of x and y as:
x=3
y=5
So, we can find the required number...
The number = 10x+y = 10*3+5=30+5=35
Then, the number = 10x+y
Number by interchanging the digit= 10y+x
According to the question,
x+y=8______________________(i)
10y+x=(10x+y)+18
9x-9y=-18
x-y=-2______________________(ii)
On solving (i) and (ii)...
We get values of x and y as:
x=3
y=5
So, we can find the required number...
The number = 10x+y = 10*3+5=30+5=35
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