Question

The sum of the digit of a three digit number is 16. If the ten's digit of the number is 3 times the unit's digit is one – fourth of the hundredth digit, then what is the number ?​

Answer 1

Answer:

$\huge\underline\bold {Answer:}$

Let the hundredth’s digit be x.

Then, unit’s digit

= x/4, ten’s digit = 3x/4

Given, x + x/4 + 3x/4 = 16

$= > \frac{4x + x + 3x}{4} = 16$

=> 2x = 16

=> x = 8

Therefore ten’s digit

= 3 × 8/4 = 6,

unit’s digit = 8/4 = 2

Therefore required number

= 100 × 8 + 10 × 6 + 2

= 800 + 60 + 2

= 862.

Answer 2

Step-by-step explanation:

Let the hundredth's digit be “x”. Then,

Unit's digit = x/4 and

ten's digit = 3x/4

ATQ,

x + x/4 + 3x/4 = 16

$= > \frac{4x + x + 3x}{4} = 16$

=> 2x = 16

=> x = 8

Ten's digit = 3x

= (3 × 8) ÷ 4

= 6

Unit's digit = 8/4 = 2

Hence required number = 100 × 8 + 10 × 6 + 2

= 800 + 60 + 2

= 862