the sum of the digit of a two digit is 7 . the number formed by reversing the digit is 45 more than the original number . find the original number
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Answered by
44
▶ Given
i) The sum of the digits of a two digit number is 7
ii) The number formed by reversing the digit is 45 more than the original number
▶ Let :
i) Let the two digit number be 10x + y, where x and y are one's and ten's digits respectively
▶ According to the Question :
The sum of the digits of the number is 7
•°• x + y = 7 ....... ( i )
After reversing the digits, the number becomes 10y + x
The number formed by reversing the digit is 45 more than the original number
•°• 10y + x - ( 10x + y ) = 45
=> 10y + x - 10x - y = 45
=> 9y - 9x = 45
=> 9 ( y - x ) = 45
=> y - x = 5
=> x - y = - 5 ....... ( ii )
Adding eq ( i ) and ( ii ) , we get :
x + y = + 7
x - y = - 5
_____________________
2x = 2
x = 1
Substituting value of x in equation ( i ), we get :
x + y = 7
=> 1 + y = 7
=> y = 7 - 1
=> y = 6
•°• The number = 10x + y
= 10 × 1 + 6
= 10 + 6
= 16
✔✔ Hence, it is solved ✅✅
Answered by
51
Answer:
→ The original number is 16 .
Step-by-step explanation:
Let the unit's digit of the original number be x .
And, the ten's digit of the original number be y .
Now, A/Q,
→ Sum of the two digits number is 7 .
∵ x + y = 7 ............(1) .
Original number = 10x + y .
Number obtained on reversing the digits = 10y + x .
A/Q,
→ The number obtained on reversing the digit is 45 more than the original number .
∵ 10x + y + 45 = 10y + x .
⇒ 10x - x + y - 10y = - 45 .
⇒ 9x - 9y = - 45 .
⇒ 9( x - y ) = - 45 .
⇒ x - y = - 45/9 .
∵ x - y = -5 ...........(2) .
On substracting equation (1) and (2), we get
x + y = 7 .
x - y = -5 .
- + +
________
⇒ 2y = 12 .
⇒ y = 12/2 .
∴ y = 6.
On putting the value of 'y' in equation (1), we get
∵ x + y = 7 .
⇒ x + 6 = 7 .
⇒ x = 7 - 6 .
∴ x = 1 .
Therefore , the original number = 10x + y .
= 10 × 1 + 6 .
= 10 + 6 .
= 16 .
Hence, the original number is 16 .
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