The sum of the digit of a two digit no. is 15. The number obtained by intercharging its digit exceeds the given no. by 9 . Find the original number
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☆ɢɪᴠᴇɴ :-
ꜱᴜᴍ ᴏꜰ ᴅɪɢɪᴛꜱ ᴏꜰ ᴀ ᴛᴡᴏ-ᴅɪɢɪᴛ ɴᴜᴍʙᴇʀꜱ ɪꜱ 15.ᴛʜᴇ ɴᴜᴍʙᴇʀ ᴏʙᴛᴀɪɴᴇᴅ ʙʏ ɪɴᴛᴇʀᴄʜᴀɴɢɪɴɢ ɪᴛꜱ ᴅɪɢɪᴛꜱ ᴇxᴄᴇᴇᴅꜱ ᴛʜᴇ ɢɪᴠᴇɴ ɴᴜᴍʙᴇʀ ʙʏ 9.
☆ᴛᴏ ꜰɪɴᴅ :-
ᴛʜᴇ ᴏʀɪɢɪɴᴀʟ ɴᴜᴍʙᴇʀ
☆ꜱᴏʟᴜᴛɪᴏɴ :-
ʟᴇᴛ ᴛʜᴇ ᴛᴇɴꜱ ᴅɪɢɪᴛ ɴᴜᴍʙᴇʀ ʙᴇ x
ᴀɴᴅ ᴛʜᴇ ᴜɴɪᴛꜱ ᴅɪɢɪᴛꜱ ɴᴜᴍʙᴇʀ ʙᴇ ʏ
ᴏʀɪɢɪɴᴀʟ ɴᴜᴍʙᴇʀ = (10x + ʏ)
ᴀᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴛʜᴇ Qᴜᴇꜱᴛɪᴏɴ
1ꜱᴛ ᴇQᴜᴀᴛɪᴏɴ
x + ʏ = 15 ……..(ɪ)
2ɴᴅ ᴇQᴜᴀᴛɪᴏɴ
ɴᴜᴍʙᴇʀ ᴏʙᴛᴀɪɴᴇᴅ ᴏɴ ʀᴇᴠᴇʀꜱɪɴɢ ɪᴛꜱ ᴅɪɢɪᴛꜱ = (10ʏ + x)
⇒ (10ʏ + x) = (10x + ʏ) + 9
⇒ 10ʏ + x – 10x – ʏ = 9
⇒ 9ʏ – 9x = 9
⇒ ʏ – x = 1 …….(ɪɪ)
ᴏɴ ᴀᴅᴅɪɴɢ (ɪ) ᴀɴᴅ (ɪɪ)
⇒ 2ʏ = 16
⇒ ʏ = 8
ᴘᴜᴛᴛɪɴɢ ᴀʟʟ ᴛʜᴇ ᴠᴀʟᴜᴇꜱ ɪɴ ᴇQ (ɪ)
⇒ x + ʏ = 15
⇒ x + 8 = 15
⇒ x = (15 – 8)
⇒ x = 7
ɴᴜᴍʙᴇʀ = (10x + ʏ)
= 10 × 7 + 8
= 70 + 8
= 78
ʜᴇɴᴄᴇ, ᴛʜᴇ ᴏʀɪɢɪɴᴀʟ ɴᴜᴍʙᴇʀ ɪꜱ 78.
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